Simple Machines - Chapter 4 Complete Revision Guide
Definitions · symbols and units · formulas · derivations · diagrams · worked examples
Jump to: Definitions · Units · Formula sheet · Levers · Derivations · Diagrams · Examples · Exam checklist
1. Essential Definitions
2. Symbols, Quantities and Units
| Quantity | Symbol | SI unit | Note |
|---|---|---|---|
| Load / effort / force | L, E, F | newton (N) | 1 N = 1 kg m s-2 |
| Length, arm, radius, pitch | l, d, R, r, p | metre (m) | Convert cm to m for N m answers |
| Moment / torque / moment of couple | τ or M | newton metre (N m) | CGS unit: dyne cm; dimensions [ML²T-2] |
| Work | W | joule (J) | 1 J = 1 N m, but work and torque are different quantities |
| Mechanical advantage | M.A. | no unit | Ratio of two forces |
| Velocity ratio | V.R. | no unit | Ratio of two distances or speeds |
| Efficiency | η | no unit or % | 0 < η ≤ 1, or 0-100% |
| Number of teeth | T or N | no unit | A count |
3. Complete Formula Sheet
General machine
M.A. = L/E
V.R. = distance by effort / distance by load
η = output work / input work
η = M.A./V.R.
Percentage efficiency = (M.A./V.R.) × 100
Resultant parallel forces
Like: R = A + B
Unlike: R = |A - B|
Position from moments:
A × distance from A = B × distance from B
Lever
Effort × effort arm = Load × load arm
M.A. = L/E = effort arm / load arm (ideal)
Inclined plane
M.A. = length/height = l/h = 1/sin θ (ideal)
E = Lh/l = L sin θ
Torque and couple
τ = Fd = Fr sin θ
d = perpendicular distance
Moment of couple = F × perpendicular separation
Equilibrium
ΣF = 0
Στ = 0
Clockwise moments = anticlockwise moments
Wheel and axle
M.A. = L/E = R/r (ideal)
One turn: effort moves 2πR; load moves 2πr
Screw jack
One turn: effort distance = 2πl
Load distance = pitch p
M.A. = 2πl/p (ideal)
Two meshing gears
Speed ratio: ωdriver/ωdriven = Tdriven/Tdriver
Adjacent external gears rotate in opposite directions
4. The Three Classes of Levers
| Class | Middle part | Pattern | M.A. | Examples |
|---|---|---|---|---|
| Class I | Fulcrum | E-F-L | May be <1, =1 or >1 | Seesaw, scissors, crowbar, pliers |
| Class II | Load | F-L-E | Always >1 ideally | Wheelbarrow, nutcracker, bottle opener |
| Class III | Effort | F-E-L | Always <1 ideally | Tweezers, fishing rod, human forearm, fire tongs |
5. Key Derivations
1. General relation η = M.A./V.R.
Efficiency η = output work/input work = (L × distance moved by load)/(E × distance moved by effort). Rearrange: η = (L/E) ÷ (distance by effort/distance by load). Therefore η = M.A./V.R. For an ideal machine η = 1, so M.A. = V.R.
2. Law of the lever
In rotational equilibrium, clockwise moment equals anticlockwise moment. If effort and load act on opposite sides of the fulcrum, E × effort arm = L × load arm. Dividing by E × load arm gives L/E = effort arm/load arm. Thus a longer effort arm produces a larger ideal M.A.
3. Mechanical advantage of an inclined plane
Let slope length be l and vertical height be h. For a smooth ideal plane, input work = E × l and useful output work = L × h. Therefore El = Lh, so M.A. = L/E = l/h. Since sin θ = h/l, M.A. = 1/sin θ. A gentler, longer slope needs less effort but requires a longer travel distance.
4. Torque formula
Only the component of force perpendicular to the radius produces rotation. That component is F sin θ, so torque = radius × perpendicular component = τ = rF sin θ. Equivalently, if d is the perpendicular distance from the pivot to the line of action, τ = Fd. Torque is greatest when θ = 90°.
5. Position of a resultant of two like parallel forces
If A and B act at M and N and their resultant R acts at O between them, take moments about O. The resultant passes through O and has zero moment there. Hence A × MO = B × NO, while R = A + B. The stronger force lies closer to the resultant.
6. Wheel and axle
In one complete revolution, the effort at wheel radius R moves 2πR while the load at axle radius r moves 2πr. For an ideal machine, E(2πR) = L(2πr). Cancelling 2π gives L/E = R/r. Thus M.A. = R/r.
7. Screw jack
For one turn, effort at a handle of length l moves around a circle of circumference 2πl. The load rises by one pitch p. Ideally, E(2πl) = Lp. Therefore M.A. = L/E = 2πl/p. Increasing handle length or decreasing pitch increases mechanical advantage.
8. Gear speed relation
At the contact point, both gears have the same tangential speed. Since circumference and tooth count are proportional, revolutions are inversely proportional to tooth count. Thus ωdriver/ωdriven = Tdriven/Tdriver. A small driver turning a large driven gear reduces speed and increases torque; reversing their roles increases speed.
6. Visual Explanations
Lever and moments
Balance occurs when E × effort arm = L × load arm. Moving the effort farther from the fulcrum reduces the effort needed.
Inclined plane
For the same height h, a longer slope l gives larger M.A. = l/h and smaller ideal effort. You trade force for distance.
Couple
Net force is zero, but the turning effects add. Moment of couple = Fd. Examples: steering wheel, tap and key.
Meshing gears
External gears rotate in opposite directions. A smaller driver turning a larger driven gear provides speed reduction and torque multiplication.
7. Worked Examples
Example 1: Mechanical advantage
A machine of M.A. 5 raises a 25 N load. M.A. = L/E, so E = L/M.A. = 25/5 = 5 N.
Example 2: Lever
A 10 N effort acts 50 cm from a fulcrum; the load is 10 cm away. M.A. = 50/10 = 5. Load = M.A. × effort = 5 × 10 = 50 N.
Example 3: Nutcracker
A class-II nutcracker has effort arm 25 cm, load arm 8 cm and effort 32 N. From E × effort arm = L × load arm: L = 32 × 25/8 = 100 N.
Example 4: Inclined plane
A smooth plank is 4 m long and 1 m high. It raises a 48 N load. M.A. = l/h = 4/1 = 4. Effort E = L/M.A. = 48/4 = 12 N.
Example 5: Torque
An 8 N force acts perpendicularly 20 cm from a pivot. Convert 20 cm = 0.20 m. τ = Fd = 8 × 0.20 = 1.6 N m.
Example 6: Longer spanner
A 120 N force on a 0.40 m spanner gives τ = 48 N m. To get the same torque with 40 N, r = τ/F = 48/40 = 1.2 m. Tripling the arm reduces the required force to one-third.
Example 7: Moment of a couple
Two opposite 4 N forces act on a steering wheel 30 cm apart. d = 0.30 m. Moment of couple = Fd = 4 × 0.30 = 1.2 N m. Do not double it; Fd already equals the sum of the two moments.
Example 8: Wheel and axle
Wheel radius R = 35 cm and axle radius r = 7 cm. M.A. = R/r = 35/7 = 5. With effort 10 N, load L = 5 × 10 = 50 N.
Example 9: Screw jack
Handle length l = 0.35 m and pitch p = 5 mm = 0.005 m. Ideal M.A. = 2πl/p = 2π(0.35)/0.005 ≈ 440. Ideally, a 20 N effort could balance an 8800 N load; a real jack lifts less because η < 100%.
Example 10: Gears
An 11-tooth driver rotates at 120 rpm and drives a 22-tooth gear. ndriven = 120 × 11/22 = 60 rpm, in the opposite direction. Speed halves while ideal torque doubles.
Example 11: Efficiency
A machine has M.A. 5 and efficiency 80% = 0.80. Since η = M.A./V.R., V.R. = 5/0.80 = 6.25. If effort moves 20 cm, load distance = 20/6.25 = 3.2 cm.
Example 12: Resultant of like parallel forces
15 N and 5 N act upward 4 m apart. R = 20 N upward. If R is x from the 15 N force, take moments about that end: 20x = 5 × 4, so x = 1 m from the 15 N force. The resultant is closer to the larger force.
8. Exam Checklist and Common Mistakes
- Mark F, L and E before deciding the class of a lever. Do not classify it by appearance.
- Use the perpendicular distance to the line of action when calculating a moment.
- Convert centimetres or millimetres to metres before giving torque in N m.
- Clockwise and anticlockwise moments have opposite signs. In equilibrium their algebraic sum is zero.
- A couple has zero resultant force but a non-zero turning effect.
- M.A., V.R. and efficiency have no units. Convert percentage efficiency to a decimal in calculations.
- For an ideal machine, input work = output work and M.A. = V.R. For a real machine, friction makes M.A. < V.R.
- A machine never reduces total ideal work: a smaller effort must move through a greater distance.
- On an inclined plane, l is the length along the slope; h is the vertical height.
- For a screw jack, use pitch in metres and handle length from the screw axis to the point where effort acts.
- Meshing external gears rotate in opposite directions. An idler gear changes direction but not the overall speed ratio.
- For like parallel forces the resultant lies between them; for unlike forces it lies outside, on the side of the larger force.